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(7H)=7(7H)^2-1
We move all terms to the left:
(7H)-(7(7H)^2-1)=0
We get rid of parentheses
-77H^2+7H+1=0
a = -77; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·(-77)·1
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{357}}{2*-77}=\frac{-7-\sqrt{357}}{-154} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{357}}{2*-77}=\frac{-7+\sqrt{357}}{-154} $
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